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**Rupali Bank Limited Exam Question Solution**

**Important Info:**

**Post: Officer (Cash)
**

Written Exam date: 28 April 2018

Exam Time: 2.30 To 4.30 PM

**Below of Rupali Bank Exam Question Image:**

**Below of Math Question Solution**

**8.**

**a) 20 weeks**

**b) A=37.5 And B=7.5**

**c) 1% loss**

d) 1

e) Table=500Tk Chair=100Tk. Total=600 Tk.

f) x=.5 or, 1/2 And y=3

g) 137 travelers

See Rupali Bank Limited (RBL) Written Math detail Solution below:

1. A family has 480 kg of rice for X number of weeks. If they need to use the same amount for 4 more weeks, they need to cut down their weekly assumption of rice by 4 kg. what is the value of X?

ATQ,

x (x+4) = 480

x² + 4x – 480 = 0

(x-20) (x+24) = 0

x = -24 or 20

ans : 20 weeks

2. If cos (A+B) = 1/√2 and Cos (A-B) = √3/2, then what is the value of A & B.

[0∘ < A+B ≤ 90∘ And A > B]

As it given, we get–

Cos 45 = 1/√2 = Cos (A+B)

So, A+B = 45

A = 45 – B –(1)

Again,

Cos 30 = √3/2 = Cos (A-B)

A-B = 30

45-B -B = 30

B = 15/2

So, A = 45 – 15/2 = 75/2

Ans : 75/2 & 15/2

3. A shopkeeper sells two shirt at the same price. He makes one on 10% profit and 10% loss on another. What is the total gain or loss percent?

Let, he sells each shirt at 990 tk

total SP = 990*2 = 1980 tk

First CP = 990/90% = 1100

Second SP = 990/110% = 900

Total CP = 1100+900 = 2000 tk

CP > SP

Loss amount = 2000-1980 = 20 tk

So, Loss Percent = (20/2000) * 100

= 1

Ans : 1% Loss

4.

a ^ (q-r)

= {xy^(p-1)}^(q-r)

= x^ (q-r) * y^ (pq – rp -q +r)

Same as

b^ (r-p) = x^(r-p) * y(qr-pq-r+p)

c^ (p-q) = x^(p-q) * y(rp -qr -p + q)

LHS = x^(q-r+r-p+p-q) * y^ (pq – rp -q + r + qr -pq -r + p + rp – qr -p +q)

= x⁰ * y⁰

= 1 * 1

= 1

= R.H.S. [ Proved ]

5. Price of 3 tables and 5 Chairs is 2000 tk. And price of 5 Tables and 7 Chairs is 3200 tk. Find the price of 1 Table and 1 chair?

=>

Table = T & Chair = C

3T + 5C = 2000

21T + 35C = 14000

35C = 14000-21T —(1)

Again,

5T + 7C = 3200

25T + 35C = 16000

25T + 14000 – 21T = 16000

T = 2000/4 = 500 TK

So,

3*500 + 5C = 2000

C = 500/5 = 100 TK

Price of 1 table & 1 Chair = 500+100 = 600 tk

Ans : 600 tk.

6. Equation solve

Given That,

1/2x + 6/y = 3

12x + y = 6xy

y = 6xy – 12x

5y = 30xy – 60x —(1)

Again, given that–

5/x + 3/y = 11

3x + 5y = 11xy

3x + 30xy – 60x = 11xy

57x = 19xy

y = 3

So,

3 = 6*x*3 – 12x

18x – 12x = 3

x = 3/6 = 1/2

At 1st equation –

1/{2 *(1/2)} + 6/3 = 3

1+ 2 = 3

At 2nd equation –

5/(1/2) + 3/3 = 11

10 + 1 = 11

Ans :: (x,y) = (1/2, 3)

7. In a survey at an airport, 55 travelers said that last year they had been to india, 53 said they had been to Nepal, 79 said they had been to Bhutan. 18 had been to india & nepal, 17 had been india & bhutan, 25 had been to nepal & bhutan, 10 had been to all three countries. How many travelers took part in the survey?

Let, Total = T

We know,

All = A+B+C + (All common) – (Two common)

ATQ,

T = 55+53+79 + 10 – (18 +17 +25)

= 197 – 60

= 137

Ans :: 137 Travelers

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**RBL Written Exam Question Solution**

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