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**Janata Bank Question Solve 2018**

**Important Info**

**Exam Type: Written Exam****Post: Executive Officer (EO)****Exam Date: 5 October 2018****Exam Time: 3.30 PM to 5.30 PM**

**Below of Janata Bank Question**

Below of Janata Bank Question Solved

1. পদ্মা সেতু বাস্তবায়ন ও বাংলাদেশের আর্থ সামাজিক উন্নয়নে ভুমিকা (৩০)

2. Current Challenges in the Banking sector in Bangladesh. Recommendation on how to reduce nonperforming loan (20)

3. Translation B2E (20)

4. Translation E2B (20)

5. You are Planning to set up a food processing factory in Rangamti. Write a letter to a bank manager to finance the factory (20)

6. Passage (20)

7. Math (3 math 25+25+20)=70

**Math answer :**

A. 100000 TK.

B. 40%

C. 3000 TK.

**Full Math Solution:**

1. Mr. Karim gave 40% of the money he had, to his wife. He also gave 20% of the remaining amount to each of his three sons. Half of the amount now left was spent on miscellaneous items and the remaining amount of Tk. 12,000 was deposited in the bank. How much money did Mr. Karim have initially?

**Explanation :**

Let the initial amount with Mr. Karim be Tk. x

Then Money is given to wife = Tk. 40100x

= Tk. 2x5 Balance = Tk. (x−2x5) = Tk. 2x5

Money is given to 3 sons = Tk. [3×(20100×3x5)]

= Tk. 9x25

Balance = Tk.(3x5−9x25)

= Tk. .6x25

The amount deposited in bank = Tk. (12×6x25)

= Tk. 3x25

3x25 = 12000 ⇔ x=(12000×253)

= 100000

So, Mr. Karim initially had Tk. 1,00,000 with him

Short-cut Method: Let the initial amount with Mr. Karim be Tk. x

Then, 12[100−(3×20)]

% of (100 – 40)% of x

= 12000

⇔ 12×40100×60100×x

= 12000 ⇔325x = 12000 ⇔ x=(12000×253) = 100000

**Ans: Tk. 100000**

2. A dealer buys dry fruits at the rate of Tk. 100, Tk. 80 and Tk. 60 per kg. He bought them in the ratio Tk. 12: 15: 20 by weight. He in total gets 20% profit by selling the first two and at last, he finds he has no gain no loss in selling the whole quantity which he had. What was the percentage loss he suffered for the third quantity?

**Solution:**

Total cost of first two variety = Tk (100×12 + 80×15) = Tk 2400.

Total gain from selling the first two variety = Tk 2400×20% = Tk 480.

So, by selling 20 kg of the third variety of fruit, the dealer suffered a loss of Tk 480.

So, loss per kg of third variety of fruit = Tk. 480 ÷ 20 = Tk 24.

Loss percentage = (24/60 × 100)% = 40%

Answer: 40%

**Alternative solution:**

Suppose, the dealer suffered a loss of Tk x by selling a kg of the third variety of fruit.

According to the question,

20x = 0.2(100×12 + 80×15)

or, 20x = 480

or, x = 24.

So, the loss percentage = (24×100/60)% = 40%

**Shortcut: ****Solution:**

3. In a business A invests 600 more than B. The capital of B remained invested for 7 1/2 months, while the capital of A remained invested for 2 months. If the total profit is Tk. 620 and B get Tk. 140 less than A gets then what is the amount of A’s Capital?

**Solution:**

Suppose, the amount of A’s capital is = Tk x

So, the amount of B’s capital is = Tk (x-600)

B’s capital remained invested for 7.5 months.

A’s capital remained invested for (7.5+2) = 9.5 months.

Suppose, the total duration of the business is n months.

Suppose,

Out of Tk 620/- profit, B gets = Tk y

So, A gets = Tk (y+140)

So,

y+140+y = 620

or, y = 240

B gets = Tk 240/-

A gets = Tk 240+140 = Tk 380/-

According to the question,

9.5x/n : 7.5(x-600)/n = 380 : 240

19x : 15(x-600) = 19 : 12

15x – 9000 = 12x

3x = 9000

x = 3000

**Answer: 3000 TK.**

**Janata Bank Exam Solution 2018**

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